Question

Write $(2x^3)^{3/4}$ as a radical expression

Original question: Write (5x)3/5(5x)^{3/5} as a radical expression. (5x)35=53x35=125x35\sqrt[5]{(5x)^3}=\sqrt[5]{5^3x^3}=\sqrt[5]{125x^3}

(2x)4/7=(2x)47=24x47=16x47(2x)^{4/7}=-\sqrt[7]{(2x)^4}=\sqrt[7]{2^4x^4}=\sqrt[7]{16x^4}

Write (2x3)3/4(2x^3)^{3/4} as a radical expression.

Expert Verified Solution

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Key concept: Rational exponents follow the rule am/n=amna^{m/n}=\sqrt[n]{a^m}. Here, the denominator 44 tells you the root, and the numerator 33 tells you the power.

Step by step

Use the rule

am/n=amna^{m/n}=\sqrt[n]{a^m}

So

(2x3)3/4=(2x3)34(2x^3)^{3/4}=\sqrt[4]{(2x^3)^3}

Now simplify inside the radical:

(2x3)3=23x9=8x9(2x^3)^3=2^3x^9=8x^9

Therefore,

(2x3)3/4=8x94\boxed{(2x^3)^{3/4}=\sqrt[4]{8x^9}}

If you want a form with a perfect fourth power pulled out, you can also write

8x94=x28x4\sqrt[4]{8x^9}=x^2\sqrt[4]{8x}

assuming x0x\ge 0 in a real-number context.

Pitfall alert

A common mistake is to put the exponent on only one part of the product, or to turn 34\frac34 into a cube root instead of a fourth root. Another frequent error is forgetting that (x3)3=x9(x^3)^3=x^9.

Try different conditions

If the expression were (2x3)1/4(2x^3)^{1/4}, then the radical form would be 2x34\sqrt[4]{2x^3}. If it were (2x3)5/4(2x^3)^{5/4}, then it would be (2x3)54\sqrt[4]{(2x^3)^5}.

Further reading

rational exponents, fourth root, radical expression

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