Question

Rewrite the exponential expression as a radical expression: $-3x^{2/3}$

Original question: Rewrite the exponential expression as a radical expression.

3x2/3-3x^{2/3}

3x23\sqrt[3]{-3x^2}

3x23-3\sqrt[3]{x^2}

Expert Verified Solution

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Expert intro: Use the fractional exponent rule and keep the negative coefficient separate from the radical unless the problem asks otherwise.

Detailed walkthrough

Start with the exponent rule:

x2/3=x23.x^{2/3}=\sqrt[3]{x^2}.

Now multiply by 3-3:

3x2/3=3x23.-3x^{2/3}=-3\sqrt[3]{x^2}.

Therefore, the radical expression is

3x23.\boxed{-3\sqrt[3]{x^2}}.

💡 Pitfall guide

Do not write 3x23\sqrt[3]{-3x^2} unless the coefficient has been intentionally moved inside the radical. That changes the value of the expression.

🔄 Real-world variant

If the exponent were 5/35/3, the radical form would be 3x53-3\sqrt[3]{x^5}. If the denominator were 22, the expression would use a square root instead of a cube root.

🔍 Related terms

fractional exponent, radical notation, cube root

FAQ

What is the radical form of $-3x^{2/3}$?

The radical form is $-3\sqrt[3]{x^2}$. The exponent $2/3$ means cube root of $x^2$, and the coefficient $-3$ stays outside.

Can the $-3$ be placed inside the radical?

Not in the direct rewrite. Moving $-3$ inside the radical changes the expression unless it is rewritten using a valid equivalent form.

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