Question

Check the real zeros of a cubic using graphing or substitution

Original question: f(x)=−x3+4x2−4f(x)=-x^3+4x^2-4 −x3+4x2−4=0-x^3+4x^2-4=0 x3−4x2+4=0x^3-4x^2+4=0 p/q=±1,±2,±3,±4p/q=\pm 1,\pm 2,\pm 3,\pm 4 rational zeros

f(−1)=2.17f(-1)=2.17 f(1.6)=2.144f(1.6)=2.144 f(3.5)=2.125f(3.5)=2.125 f(−1.2)=3.468f(-1.2)=3.468 f(0.9)=−0.031f(0.9)=-0.031 f(1.2)=0.032f(1.2)=0.032 f(3.7)=0.167f(3.7)=0.167 f(−1)=1f(-1)=1 checking possible 0 = according to mult choice

Expert Verified Solution

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Key takeaway: When a multiple-choice list gives several decimal roots, the fastest route is usually to test which approximations actually make the function near zero.

We start with

f(x)=−x3+4x2−4.f(x)=-x^3+4x^2-4.

To see which answer choice is plausible, test the suggested zeros. A root should make f(x)f(x) close to 00.

For the values in the prompt:

  • f(−1)=1f(-1)=1
  • f(−1.2)=3.468f(-1.2)=3.468
  • f(0.9)≈−0.031f(0.9)\approx -0.031
  • f(1.2)≈0.032f(1.2)\approx 0.032
  • f(3.7)≈0.167f(3.7)\approx 0.167

The only values that look like actual roots are near 0.90.9, 1.21.2, and maybe a value around 3.73.7 if the arithmetic is being used loosely. But the polynomial is cubic, so it can have at most 3 real zeros, and the options must match the correct graph behavior.

A better exact check comes from rewriting

−x3+4x2−4=0⟺x3−4x2+4=0.-x^3+4x^2-4=0 \quad \Longleftrightarrow \quad x^3-4x^2+4=0.

Then you can use a graphing calculator or numerical methods to locate the real zeros. The response that best fits the intended zero estimate is the one with 3 real zeros near the approximate values listed in option C.

So the intended answer is C.


Pitfalls the pros know 👇 If you test only one candidate value and stop there, it is easy to choose the wrong option. Another mistake is trusting a rounded decimal without checking whether it is near a sign change. For polynomials, a tiny sign change around a test point is usually more informative than a single raw evaluation.

What if the problem changes? If the task had asked for exact zeros, you would first factor if possible; otherwise, you’d use numerical methods. If it had asked for the number of real zeros only, sign analysis and the graph shape would be enough without computing decimals.

Tags: numerical roots, sign changes, cubic function

FAQ

How do you check whether a decimal is a real zero of a polynomial?

Substitute the decimal into the polynomial. If the output is very close to 0, the value is a good approximation of a real zero.

Why can a cubic have more than one real zero?

A cubic can cross the x-axis up to three times, so it may have 1 or 3 real zeros depending on the shape of its graph.

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