Question

Solving for λ and μ in Vector Equation λr + μs = t

Original question: (c) the value of the constants λ\lambda and μ\mu when λr+μs=t\lambda r+\mu s=t. (4 marks)

Expert Verified Solution

thumb_up100%(1 rated)

Since you haven't provided the specific vectors r,s,r, s, and tt, I will demonstrate the method using a general approach. To solve for scalars λ\lambda and μ\mu in a vector equation of the form λr+μs=t\lambda \vec{r} + \mu \vec{s} = \vec{t}, we use the property of linear independence in 2D or 3D space.

Answer

To find the constants λ\lambda and μ\mu, express the equation as a system of linear equations by equating the components (i and j, or x and y) on both sides. Solve the resulting system using substitution or elimination methods.

Explanation

  1. Set up the vector equation Write the vectors r,s,\vec{r}, \vec{s}, and t\vec{t} in component form. If r=(r1r2)\vec{r} = \begin{pmatrix} r_1 \\ r_2 \end{pmatrix}, s=(s1s2)\vec{s} = \begin{pmatrix} s_1 \\ s_2 \end{pmatrix}, and t=(t1t2)\vec{t} = \begin{pmatrix} t_1 \\ t_2 \end{pmatrix}, the equation becomes: λ(r1r2)+μ(s1s2)=(t1t2)\lambda \begin{pmatrix} r_1 \\ r_2 \end{pmatrix} + \mu \begin{pmatrix} s_1 \\ s_2 \end{pmatrix} = \begin{pmatrix} t_1 \\ t_2 \end{pmatrix} We multiply the scalar constants by the respective vector components.

  2. Form a system of linear equations Extract the individual equations by equating the horizontal (xx) components and vertical (yy) components: 1)λr1+μs1=t11) \quad \lambda r_1 + \mu s_1 = t_1 2)λr2+μs2=t22) \quad \lambda r_2 + \mu s_2 = t_2 This creates two equations with two unknowns, which is solvable for any non-parallel vectors.

  3. Solve for the constants Use either elimination or substitution. For instance, multiply equation (1) by r2r_2 and equation (2) by r1r_1 to align the λ\lambda terms, then subtract them to eliminate λ\lambda and solve for μ\mu. Once μ\mu is found, substitute it back into either equation to find λ\lambda. Solving the system isolates the values of λ\lambda and μ\mu that satisfy the linear combination.

Final Answer

The values of λ\lambda and μ\mu are found by solving the simultaneous system derived from the vector components: λ=,μ=\boxed{\lambda = \dots, \mu = \dots}

Common Mistakes

  • Component Mixing: Students often add or subtract vectors incorrectly by accidentally combining the xx-component of one vector with the yy-component of another. Always write them out in columns to stay organized.
  • Sign Errors: Forgetting to distribute the negative sign when multiplying by a negative scalar or when performing elimination/subtraction. Always distribute the scalar to both components of the vector.

Tutor Note: If you provide the specific vectors r,s,\vec{r}, \vec{s}, and t\vec{t} from your worksheet, I can calculate the exact numerical values for you immediately!

chat