Question
-3x^{2/3}
Original question: -3x^{2/3} ; ³\sqrt{-3x^2}; ³\sqrt{-3x^2}=; ³\sqrt{9x^2} -3x^{2/3}=; ³\sqrt{(3x)^2}=; ³\sqrt{-3x^2}=; ³\sqrt{9x^2}
Expert Verified Solution
Expert intro: This is a direct rational-exponent conversion. The exponent means cube root of the square, and the coefficient stays outside.
Detailed walkthrough
Use the rule
So
That is the correct radical form:
You can also verify that this keeps the value unchanged for real .
💡 Pitfall guide
Do not rewrite it as unless the original expression is exactly inside the radical. Also, do not change the exponent into a square root; the denominator 3 means cube root.
🔄 Real-world variant
If the coefficient were positive, . If the exponent were , then the expression would be .
🔍 Related terms
cube root, fractional exponent, coefficient
FAQ
What is the radical form of $-3x^{2/3}$?
The radical form is $-3\sqrt[3]{x^2}$.
Why is the coefficient outside the radical?
Because only the variable part has the fractional exponent. The factor -3 multiplies the radical from outside.