Question

Convert a real number to polar form

Original question: Write the following numbers in the polar form r(cosϕ+isinϕ)r(\cos\phi + i\sin\phi), 0ϕ<2π0 \le \phi < 2\pi. (a) 33 r=r = ________, ϕ=\phi = ________,

Expert Verified Solution

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Expert intro: For a positive real number, polar form is one of the easiest cases: the point lies on the positive real axis, so the angle is zero.

Detailed walkthrough

A complex number in polar form is written as

r(cosϕ+isinϕ)r(\cos\phi+i\sin\phi)

For the number 33:

  • Magnitude: r=3=3r=|3|=3
  • Angle: since it lies on the positive real axis, ϕ=0\phi=0

So the polar form is

3(cos0+isin0)3(\cos 0+i\sin 0)

If your worksheet wants the blanks filled in:

  • r=3r=3
  • ϕ=0\phi=0

💡 Pitfall guide

Do not overthink the angle for a positive real number. Some students try to force a nonzero angle, but 00 is the standard principal value in 0ϕ<2π0\le \phi<2\pi. Also, keep rr nonnegative in polar form.

🔄 Real-world variant

If the number were a negative real number like 3-3, the modulus would still be r=3r=3, but the angle would be ϕ=π\phi=\pi instead of 00. That is the main change when moving from positive to negative real values.

🔍 Related terms

polar form, complex numbers, argument

FAQ

What is the polar form of 3?

The number 3 has modulus r = 3 and principal argument φ = 0, so its polar form is 3(cos 0 + i sin 0).

Why is the angle 0 for a positive real number?

Because a positive real number lies on the positive real axis, which corresponds to an angle of 0 in the standard principal range 0 ≤ φ < 2π.

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