Question

How to find the equation after stretching and shifting a quadratic graph

Original question: 6. f(x)=x2+3x4f(x)=x^2+3x-4 Case A:

  • horizontal stretch by a scale factor of 2
  • translation of 3 units towards the negative y-axis f(x2)f(x2)f\left(\frac{x}{2}\right)-f\left(\frac{x}{2}\right) Case B: translation of 3 units toward the negative y-axis and horizontal stretch by a scale factor of 2. g(x)=x24+3x27g(x)=\frac{x^2}{4}+\frac{3x}{2}-7 [x2+3x4]  m3[x^2+3x-4]\;\text{m}-3 x2+3x7x^2+3x-7 (x2)2+3(x2)7\left(\frac{x}{2}\right)^2+3\left(\frac{x}{2}\right)-7 x24+3x27\frac{x^2}{4}+\frac{3x}{2}-7

Expert Verified Solution

thumb_up100%(1 rated)

Expert intro: When a quadratic is transformed, the safest method is to apply one change at a time and only expand at the end.

Detailed walkthrough

Start with

f(x)=x2+3x4.f(x)=x^2+3x-4.

A horizontal stretch by factor 2 gives

f(x2)=(x2)2+3(x2)4.f\left(\frac{x}{2}\right)=\left(\frac{x}{2}\right)^2+3\left(\frac{x}{2}\right)-4.

Then translating the graph down 3 units means subtract 3:

g(x)=f(x2)3.g(x)=f\left(\frac{x}{2}\right)-3.

Now simplify:

=\frac{x^2}{4}+\frac{3x}{2}-7.$$ So the transformed function is $$\boxed{g(x)=\frac{x^2}{4}+\frac{3x}{2}-7}.$$ If you compare the two transformation orders in the prompt, the result is the same here because the vertical translation is just a constant shift. ### 💡 Pitfall guide Do not replace $x$ with $2x$ for a stretch by factor 2. That reverses the effect. Also, avoid subtracting 3 inside the input; the downwards shift belongs outside the function. ### 🔄 Real-world variant If the same graph were stretched horizontally by factor 3 instead, you would use $f(x/3)$. The final expression would become $$\left(\frac{x}{3}\right)^2+3\left(\frac{x}{3}\right)-4-3.$$ The method stays the same; only the input scale changes. ### 🔍 Related terms quadratic function, graph transformations, horizontal stretch

FAQ

What is the transformed equation of f(x)=x^2+3x-4 after a horizontal stretch by 2 and a shift down 3?

The transformed function is g(x)=f(x/2)-3, which simplifies to g(x)=x^2/4+3x/2-7.

Why is f(x/2) used for a horizontal stretch by 2?

Replacing x with x/2 makes every x-coordinate twice as large, which creates a horizontal stretch by factor 2.

chat