Question

How do you solve angle and arc questions in a tangent circle diagram?

Original question: 14. VQ is tangent to ⊙O at Q. QS is a diameter of ⊙O. PQ=115\overset{\frown}{PQ}=115^{\circ}, mRPS=36m\angle RPS=36^{\circ}

Find

a. R\angle R

b. S\angle S

c. SR\overset{\frown}{SR}

d. QR\overset{\frown}{QR}

e. QPR\angle QPR

f. QPS\angle QPS

g. QTP\angle QTP

h. PQV\angle PQV

i. PRQ\overset{\frown}{PRQ}

j. RSP\overset{\frown}{RSP}

k. VQS\angle VQS

l. QOP\angle QOP

Expert Verified Solution

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Key concept: Problems like this usually mix three tools: tangent-radius facts, inscribed angles, and arc relationships. Once you spot which angle belongs to which arc, the rest becomes a chain of substitutions.

Step by step

Step 1: Use the circle facts you know

Here are the rules that usually drive the whole problem:

  • A tangent is perpendicular to the radius at the point of tangency.
  • An inscribed angle equals half its intercepted arc.
  • A central angle equals the measure of its intercepted arc.
  • A diameter subtends a semicircle, so that arc is 180180^\circ.

Step 2: Start from the given measures

You are given:

  • PQ=115\overset{\frown}{PQ}=115^\circ
  • mRPS=36m\angle RPS=36^\circ
  • QSQS is a diameter
  • VQVQ is tangent at QQ

From RPS=36\angle RPS=36^\circ, the intercepted arc RSRS is:

RS=236=72\overset{\frown}{RS}=2\cdot 36^\circ=72^\circ

Step 3: Use the diameter

Since QSQS is a diameter, each semicircle measures 180180^\circ. So the arc from QQ to SS through PP and RR must fit into that semicircle depending on the diagram order.

If the points are arranged on the same arc path as listed, then the remaining arcs are found by subtraction from 180180^\circ or by using the full circle total of 360360^\circ.

Step 4: Use tangent and inscribed-angle facts

Because VQVQ is tangent at QQ:

PQV=12PQ\angle PQV = \frac{1}{2}\overset{\frown}{PQ}

so

PQV=1152=57.5\angle PQV = \frac{115^\circ}{2}=57.5^\circ

Also, the angle between tangent QVQV and chord QSQS is 9090^\circ because a tangent is perpendicular to the radius, and QSQS is a diameter through the center.

Step 5: Build the remaining angles from the diagram order

The exact values of the labeled angles R\angle R, S\angle S, QPR\angle QPR, QPS\angle QPS, QTP\angle QTP, VQS\angle VQS, and the arcs QR\overset{\frown}{QR}, PRQ\overset{\frown}{PRQ}, RSP\overset{\frown}{RSP} depend on the placement of the points in the missing diagram.

The reliable way to finish is:

  1. convert any inscribed angle to its intercepted arc,
  2. use the semicircle 180180^\circ from QSQS,
  3. use the full circle 360360^\circ for arc totals,
  4. use tangent-radius perpendicularity at QQ.

So the one value we can determine immediately from the text is:

RS=72\overset{\frown}{RS}=72^\circ

and

PQV=57.5\angle PQV=57.5^\circ

Pitfall alert

Do not treat a tangent like an ordinary secant. The tangent at QQ is perpendicular to the radius, and that fact is easy to miss. Another trap is assuming every angle label can be solved from the text alone when the missing diagram controls the arc order.

Try different conditions

If the diagram shows a different order of points on the circle, the arc subtraction changes even though the circle facts stay the same. The method does not change: inscribed angle means half the arc, central angle equals the arc, and a diameter always gives 180180^\circ for a semicircle.

Further reading

inscribed angle, tangent line, intercepted arc

FAQ

What circle theorems are used in tangent-and-arc problems?

The main tools are the tangent-radius perpendicular fact, the inscribed angle theorem, the central angle rule, and the fact that a diameter creates a semicircle of 180 degrees.

Can you solve every value without the diagram?

Not always. Some values depend on the exact order of points on the circle, so the diagram is needed to determine which arcs are intercepted by each angle.

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