Question
Find the step where the circle-equation work goes wrong
Original question: 6. Kevin's work for deriving the equation of a circle is shown below. EXPLAIN YOUR ANSWER.
x^2 + 4x = -y^2 + 20 STEP 1 x^2 + 4x = -y^2 + 20 STEP 2 x^2 + 4x = y^2 + 20 STEP 3 (x + 2)^2 = y^2 + 20 - 4 STEP 4 (x + 2)^2 - y^2 = 16
In which step did he make an error in his work?
- Step 1
- Step 2
- Step 3
- Step 4
Expert Verified Solution
Key concept: When a circle equation is being rewritten, the safest move is to check each transformation line by line. One sign error can change the whole result, even if later steps look neat.
Step by step
Start with the given equation:
Now compare Kevin’s steps.
Step 1
He rewrites the equation exactly as given:
That part is fine.
Step 2
He changes it to
This is the mistake. The term should not become unless you multiply the entire equation by or move the term properly with opposite sign. He changed only one side’s sign incorrectly.
Quick check
If you wanted to move to the left side, you would add to both sides:
That is not what Kevin wrote.
Therefore
The first error happens in Step 2.
Correct choice: 2) Step 2
Pitfall alert
A common trap is to trust the later perfect-looking square completion and ignore the earlier sign change. In algebra, one wrong sign can still lead to a clean-looking but false final form. Always check whether the same operation was applied to both sides.
Try different conditions
If Kevin had instead written
then he could complete the square on :
which becomes
That would describe a circle with center and radius .
Further reading
circle equation, completing the square, sign error
FAQ
In which step did Kevin make the first error?
The first error is in Step 2. The term -y^2 was changed to y^2 incorrectly; that sign change is not valid unless the whole equation is handled consistently.
Why is Step 1 correct?
Step 1 simply restates the original equation without changing anything, so it is correct.