Question

$SA = 2\pi(6^2) + 2\pi(6)(2)$

Original question: SA=2π(62)+2π(6)(2)SA = 2\pi(6^2) + 2\pi(6)(2)

SA=2π(6+2)SA = 2\pi(6 + 2)

SA=6π(6+2)SA = 6\pi(6 + 2)

SA=62π(6+2)SA = 6\cdot 2\pi(6 + 2)

Expert Verified Solution

thumb_up100%(1 rated)

Key concept: This is a simplification problem. The goal is to factor the expression correctly and keep track of the common terms.

Step by step

Start with

SA=2π(62)+2π(6)(2)SA = 2\pi(6^2) + 2\pi(6)(2)

Step 1: Evaluate the powers and products

62=366^2=36

So

SA=2π(36)+2π(12)SA = 2\pi(36) + 2\pi(12)

Step 2: Factor out the common factor

Both terms have a factor of 2π(6)2\pi(6):

SA=2π(6)(6)+2π(6)(2)SA = 2\pi(6)(6) + 2\pi(6)(2)

Factor out 2π(6)2\pi(6):

SA=2π(6)(6+2)SA = 2\pi(6)(6+2)

Step 3: Match the intended simplified form

Since 2π(6)=12π2\pi(6)=12\pi,

SA=12π(6+2)SA = 12\pi(6+2)

This is also the same as

SA=62π(6+2)SA = 6\cdot 2\pi(6+2)

Pitfall alert

Do not combine 626^2 with 22 before evaluating the square. Also, be careful not to drop a factor when factoring the expression.

Try different conditions

If the expression were SA=2πr2+2πrhSA=2\pi r^2+2\pi rh, you would factor it as 2πr(r+h)2\pi r(r+h). The same factoring pattern applies here.

Further reading

surface area, factoring, common factor

FAQ

How do you simplify 2π(6^2) + 2π(6)(2)?

First evaluate 6^2 = 36, then factor the common term 2π(6) to get 2π(6)(6 + 2), which is also 12π(6 + 2).

What is the main factoring idea here?

Look for the common factor in both terms and factor it out before simplifying further.

chat