Question

How to check whether a product function has a horizontal tangent at a point

Original question: 1. Determine if y=f(x)g(x)y = f(x)g(x) has a horizontal tangent at x=1x = 1.

Expert Verified Solution

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Key concept: For a product like f(x)g(x)f(x)g(x), a horizontal tangent happens exactly when the derivative is zero at that xx-value. The product rule is the key move.

Step by step

To determine whether y=f(x)g(x)y=f(x)g(x) has a horizontal tangent at x=1x=1, use the derivative.

Step 1: Differentiate with the product rule

y=f(x)g(x)+f(x)g(x)y' = f'(x)g(x) + f(x)g'(x)

Step 2: Evaluate at x=1x=1

y(1)=f(1)g(1)+f(1)g(1)y'(1)=f'(1)g(1)+f(1)g'(1)

Step 3: Check the result

  • If y(1)=0y'(1)=0, then the graph has a horizontal tangent at x=1x=1.
  • If y(1)0y'(1)\neq 0, then it does not.

So the answer depends on the values of f(1)f(1), g(1)g(1), f(1)f'(1), and g(1)g'(1). Without those numbers, you cannot decide yes or no.

Pitfall alert

Don’t assume a product has a horizontal tangent just because one factor is zero. You need the derivative at the point, not just the function value. Also, if the problem gives only the formula and no values, the question is incomplete.

Try different conditions

If you were told that f(1)=2f(1)=2, f(1)=0f'(1)=0, g(1)=3g(1)=-3, and g(1)=4g'(1)=4, then

y(1)=0(3)+24=8y'(1)=0\cdot(-3)+2\cdot 4=8

so there would be no horizontal tangent. If instead the derivative came out to 00, then the tangent would be horizontal.

Further reading

product rule, horizontal tangent, derivative at a point

FAQ

How do you check whether $y=f(x)g(x)$ has a horizontal tangent at $x=1$?

Differentiate using the product rule: $y'=f'(x)g(x)+f(x)g'(x)$. Then evaluate at $x=1$. If $y'(1)=0$, the tangent is horizontal; otherwise, it is not.

What information do you need to decide this?

You need the values of $f(1)$, $g(1)$, $f'(1)$, and $g'(1)$. Without them, the derivative at $x=1$ cannot be determined.

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