Question

Are one-to-one functions either always increasing or always decreasing

Original question: 4. Are one-to-one functions either always increasing or always decreasing? Why or why not? 5. How do you find the inverse of a function algebraically?

Expert Verified Solution

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Key concept: A one-to-one function means different inputs give different outputs. That condition is about uniqueness, not necessarily about monotonic behavior.

Step by step

No. A one-to-one function does not have to be always increasing or always decreasing.

Why not?

A function is one-to-one if it never gives the same output for two different inputs. That only means it passes the horizontal line test.

But a function can be one-to-one even if it changes direction, as long as it never repeats an output value.

Example

Consider a function defined on a restricted domain, such as a curve that goes up, then down, but still never takes the same yy-value twice on that domain. It is one-to-one, but not monotonic.

Important distinction

  • Increasing/decreasing describes how the function changes as xx increases.
  • One-to-one describes whether output values are repeated.

So the correct answer is:

No, one-to-one functions are not always increasing or always decreasing.\boxed{\text{No, one-to-one functions are not always increasing or always decreasing.}}

Pitfall alert

Do not confuse injective behavior with monotonic behavior. A function can be one-to-one on a limited domain without being globally increasing or decreasing.

Try different conditions

For many functions on an interval, strict monotonicity does imply one-to-one. For example, f(x)=x3f(x)=x^3 is strictly increasing and one-to-one. But the converse is not always true unless extra conditions are given.

Further reading

one-to-one, horizontal line test, monotonic

FAQ

Are one-to-one functions always increasing or decreasing?

No. One-to-one means no output value is repeated, but a function does not have to be monotonic to be one-to-one.

How do you find the inverse of a function algebraically?

Replace f(x) with y, swap x and y, then solve for y. The resulting expression is the inverse function if the original function is one-to-one.

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