Question

Rewrite the radical expression as an exponential expression: $-\sqrt[3]{2x^8}$

Original question: Rewrite the radical expression as an exponential expression. 2x83-\sqrt[3]{2x^8} 2(13)x(83)-2\left(\frac{1}{3}\right)x\left(\frac{8}{3}\right) (2x8)13-(2x^8)^{\frac{1}{3}}

Expert Verified Solution

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Expert intro: To rewrite a radical as an exponential expression, convert the radical index to a rational exponent and keep any outside negative sign unchanged.

Detailed walkthrough

We use the rule

an=a1n\sqrt[n]{a}=a^{\frac{1}{n}}

So

2x83=(2x8)13-\sqrt[3]{2x^8} = -(2x^8)^{\frac{1}{3}}

This keeps the negative sign in front and rewrites the cube root as an exponent.

💡 Pitfall guide

A common mistake is to write the negative sign inside the radical without reason. The expression is already negative outside, so the correct exponential form is (2x8)1/3-(2x^8)^{1/3}, not (2x8)1/3(-2x^8)^{1/3}.

🔄 Real-world variant

If the expression were 2x83\sqrt[3]{-2x^8}, then the negative would be inside the base. That would be written as (2x8)1/3(-2x^8)^{1/3}.

🔍 Related terms

rational exponents, cube root, radical notation

FAQ

How do you rewrite $-\sqrt[3]{2x^8}$ as an exponential expression?

Use rational exponents: $-\sqrt[3]{2x^8}=-(2x^8)^{1/3}$.

What rule converts a radical to an exponent?

In general, $\sqrt[n]{a}=a^{1/n}$. For a cube root, the exponent is $1/3$.

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