Question

Derivative of a composed constant-input function

Original question: 7. Find dydx\frac{dy}{dx} for y=f(g(3))y = f(g(3)).

Expert Verified Solution

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Key takeaway: This one looks like a chain rule problem, but there is a small twist: the inner expression g(3)g(3) is a constant, not a variable in xx. That changes everything.

We are given

y=f(g(3))y=f(g(3))

and asked to find

dydx\frac{dy}{dx}

Step 1: Notice what depends on xx

The expression g(3)g(3) is a constant, because the input is fixed at 3. So f(g(3))f(g(3)) is also just a constant number.

Step 2: Differentiate a constant

The derivative of a constant with respect to xx is

dydx=0\frac{dy}{dx}=0

Final answer

0\boxed{0}


Pitfalls the pros know 👇 The biggest mistake is to apply the chain rule as if the inside were g(x)g(x). It is not. Since the input is fixed at 3, there is no xx left in the expression, so the derivative is simply zero.

What if the problem changes? If the problem had been y=f(g(x))y=f(g(x)), then the chain rule would give

dydx=f(g(x))g(x)\frac{dy}{dx}=f'(g(x))g'(x)

That version is different because the inner function actually depends on xx.

Tags: chain rule, constant function, composition

FAQ

What is the derivative of y = f(g(3))?

Since g(3) is a constant, f(g(3)) is also a constant. The derivative with respect to x is 0.

Why is the chain rule not used here?

The chain rule applies when the inside depends on x. Here the input is fixed at 3, so no x remains in the expression.

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