Question

Theorem 2. Let $s_0 = \sigma_0 + i t_0$ be a fixed complex number

Original question: Theorem 2. Let s0=σ0+it0s_0 = \sigma_0 + i t_0 be a fixed complex number with σ0(12,1)\sigma_0 \in (\frac{1}{2},1) and for r>0r > 0 let g:K={sC:ss0r}Cg : K = \{s \in \mathbf{C} : |s-s_0| \le r\} \to \mathbf{C} be a continuous non-vanishing function which is analytic in the interior. Let δ0(0,1),ε(0,min(1,log(σ0)))\delta_0 \in (0,1), \varepsilon \in (0,\min(1,\log(\sigma_0))). Assume that N=N(δ0,ε)N = N(\delta_0,\varepsilon) is a positive integer for which (maxss0=rg(s))δ0N1δ0<ε3.\left(\max_{|s-s_0|=r} |g(s)|\right) \frac{\delta_0^N}{1-\delta_0} < \frac{\varepsilon}{3}. Then, there exists τ[Tt0,T+Ht0]\tau \in [T-t_0, T+H-t_0] for which TτHTT^\tau \le H \le T and maxss0=rK(s+iτ)g(s)<ε\max_{|s-s_0|=r} |K(s+i\tau)-g(s)| < \varepsilon for any δ[0,δ0]\delta \in [0,\delta_0] satisfying (maxss0=rK(s+iτ))δN1δ<ε3\left(\max_{|s-s_0|=r} |K(s+i\tau)|\right) \frac{\delta^N}{1-\delta} < \frac{\varepsilon}{3} provided that Tmax{exp2(C2(N,σ0)(B(N,g,σ0,δ0,r,ε))1η0+σ0+1ω),r}.T \ge \max\left\{ \exp_2\left(C_2(N,\sigma_0)\left(B(N,g,\sigma_0,\delta_0,r,\varepsilon)\right)^{\frac{1}{\eta_0+\sigma_0+\frac{1}{\omega}}}\right), r\right\}. Here C2(N,σ0)C_2(N,\sigma_0) is a positive, effectively computable constant depending on N,σ0N,\sigma_0 and B(N,g,σ0,δ0,r,ε)=logg(s0)+(1+g(s0))exp(σ0)ε(Gg(s0))(N1)2,B(N,g,\sigma_0,\delta_0,r,\varepsilon)=|\log g(s_0)|+\frac{(1+|g(s_0)|)\exp(\sigma_0)}{\varepsilon}\left(\frac{|G|}{|g(s_0)|}\right)^{(N-1)^2}, where G=0kN11k!g(k)(s0).|G|=\sum_{0\le k\le N-1}\left|\frac{1}{k!}g^{(k)}(s_0)\right|.

Expert Verified Solution

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Expert intro: This is a theorem statement in complex analysis / analytic number theory style. The best support here is to organize the hypotheses, the conclusion, and the role of each constant clearly.

Detailed walkthrough

What the theorem says

The statement gives a set of hypotheses on a function gg defined on a closed disk

K={sC:ss0r},K=\{s\in\mathbf{C}:|s-s_0|\le r\},

where s0=σ0+it0s_0=\sigma_0+it_0 and σ0(12,1)\sigma_0\in\left(\frac12,1\right).

Under these assumptions, and for suitable choices of the parameters δ0\delta_0, ε\varepsilon, and a sufficiently large TT, the theorem guarantees the existence of a shift τ[Tt0,T+Ht0]\tau\in[T-t_0,\,T+H-t_0] such that the translated function K(s+iτ)K(s+i\tau) approximates g(s)g(s) uniformly on the circle ss0=r|s-s_0|=r:

maxss0=rK(s+iτ)g(s)<ε.\max_{|s-s_0|=r}|K(s+i\tau)-g(s)|<\varepsilon.

It also imposes a further smallness condition involving

maxss0=rK(s+iτ)δN1δ<ε3.\max_{|s-s_0|=r}|K(s+i\tau)|\frac{\delta^N}{1-\delta}<\frac{\varepsilon}{3}.

How to read the assumptions

The theorem requires:

  • gg to be continuous and nonvanishing on KK
  • gg to be analytic in the interior of KK
  • a numerical condition on NN ensuring that

(maxss0=rg(s))δ0N1δ0<ε3\left(\max_{|s-s_0|=r}|g(s)|\right)\frac{\delta_0^N}{1-\delta_0}<\frac{\varepsilon}{3}

  • a lower bound on TT involving the constants C2C_2 and BB

Meaning of the conclusion

The conclusion is an approximation statement: after shifting by iτi\tau, the function KK can be made arbitrarily close to the target function gg on the boundary of the disk. The theorem is therefore a controlled existence result, with explicit constants and explicit dependence on the parameters.

Structure of the bound

The bound on TT has the form

Tmax{exp2(C2(N,σ0)(B(N,g,σ0,δ0,r,ε))1η0+σ0+1ω),r}.T\ge \max\left\{\exp_2\left(C_2(N,\sigma_0)\left(B(N,g,\sigma_0,\delta_0,r,\varepsilon)\right)^{\frac{1}{\eta_0+\sigma_0+\frac{1}{\omega}}}\right),r\right\}.

This says that the theorem becomes effective once TT is large enough relative to the complexity of the target function and the chosen approximation tolerance.

Final takeaway

The theorem provides a quantitative approximation result for a complex-analytic function after vertical translation, with explicit control through ε\varepsilon, NN, and the constants C2C_2 and BB.

💡 Pitfall guide

A common mistake is to lose track of where the maximum is taken. The inequalities are on the boundary circle ss0=r|s-s_0|=r, not on the whole disk. Another pitfall is treating C2C_2, BB, and NN as interchangeable; each has a distinct role in the bound.

🔄 Real-world variant

If the target tolerance ε\varepsilon is made smaller, the condition on NN becomes stricter and the required lower bound on TT typically grows. If gg were simpler or smaller on the boundary, the quantity B(N,g,σ0,δ0,r,ε)B(N,g,\sigma_0,\delta_0,r,\varepsilon) could also become smaller, improving the bound.

🔍 Related terms

complex analysis, uniform approximation, analytic function

FAQ

What is the main conclusion of the theorem?

The theorem guarantees the existence of a shift $\tau$ such that the translated function $K(s+i\tau)$ approximates $g(s)$ uniformly on the boundary circle $|s-s_0|=r$ within any prescribed tolerance $\varepsilon$, provided the stated conditions hold.

Which set is used for the maximum in the theorem?

The maximum is taken over the boundary circle $|s-s_0|=r$, not over the entire disk $|s-s_0|\le r$.

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