Exact value practice with sine, cosine, secant, cotangent, and cosecant
Original question: 1. Evaluate each of the following (exact values only)
a) sin3π−cos6π b) sec6π+2cot4π c) sin26π+cos24π
d) 4sin4π+sec2π e) 3csc6π−sin22π
Expert Verified Solution
thumb_up100%(1 rated)
Key takeaway: These expressions are built from standard unit-circle values. Once you know the special angles, each part falls out cleanly.
Evaluate each expression exactly.
a) sin3π−cos6π
sin3π=23,cos6π=23
So
sin3π−cos6π=0.
b) sec6π+2cot4π
sec6π=cos6π1=3/21=32=323,
and
cot4π=1.
Thus
sec6π+2cot4π=323+2.
c) sin26π+cos24π
sin6π=21⇒sin26π=41,
cos4π=22⇒cos24π=21.
So
41+21=43.
d) 4sin4π+sec2π
4sin4π=4⋅22=22,
and
secπ=cosπ1=−11=−1⇒sec2π=1.
Therefore
4sin4π+sec2π=22+1.
e) 3csc6π−sin22π
csc6π=sin6π1=2,
so
3csc6π=32.
Also,
sin2π=1⇒sin22π=1.
Thus
3csc6π−sin22π=32−1.
Final answers
a) 0
b) 323+2
c) 43
d) 22+1
e) 32−1
Pitfalls the pros know 👇
Two places people slip are reciprocal functions and exponents. Remember that secx=1/cosx and cscx=1/sinx, then square only after the reciprocal is taken. Also, sec2π means (secπ)2, not sec(2π).
What if the problem changes?
If the angles were replaced with nearby special angles, the method would be the same: evaluate the base trig value first, then apply any reciprocal, power, or root. If an angle is not a standard one, you would usually need a calculator approximation instead of an exact radical form.
Tags: unit circle values, reciprocal identities, special angles
FAQ
How do I evaluate exact trig expressions with sec, cot, and csc?
Rewrite reciprocal functions using sine and cosine, then substitute known unit-circle values for special angles such as pi/6, pi/4, pi/3, and pi/2.
Why does sec^2(pi) equal 1?
Because sec(pi) = 1/cos(pi) = -1, and squaring gives (-1)^2 = 1.